(x^2)y+dy=(2x^2)dx

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Solution for (x^2)y+dy=(2x^2)dx equation:


Simplifying
(x2) * y + dy = (2x2) * dx

Multiply x2 * y
x2y + dy = (2x2) * dx

Reorder the terms:
dy + x2y = (2x2) * dx

Remove parenthesis around (2x2)
dy + x2y = 2x2 * dx

Multiply x2 * dx
dy + x2y = 2dx3

Solving
dy + x2y = 2dx3

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2dx3' to each side of the equation.
dy + -2dx3 + x2y = 2dx3 + -2dx3

Reorder the terms:
-2dx3 + dy + x2y = 2dx3 + -2dx3

Combine like terms: 2dx3 + -2dx3 = 0
-2dx3 + dy + x2y = 0

Add '-1x2y' to each side of the equation.
-2dx3 + dy + x2y + -1x2y = 0 + -1x2y

Combine like terms: x2y + -1x2y = 0
-2dx3 + dy + 0 = 0 + -1x2y
-2dx3 + dy = 0 + -1x2y
Remove the zero:
-2dx3 + dy = -1x2y

Combine like terms: -1x2y + x2y = 0
-2dx3 + dy + x2y = 0

The solution to this equation could not be determined.

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